如何解决Android 5.0中出现的警告:Service Intent must be explicit

有些时候我们使用Service的时需要采用隐私启动的方式,但是Android 5.0一出来后,其中有个特性就是Service Intent must be explitict,也就是说从Lollipop开始,service服务必须采用显示方式启动。
而android源码是这样写的

源码位置:sdk/sources/android-21/android/app/ContextImpl.java

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private void validateServiceIntent(Intent service) {
if (service.getComponent() == null && service.getPackage() == null) {
if (getApplicationInfo().targetSdkVersion >= Build.VERSION_CODES.LOLLIPOP) {
IllegalArgumentException ex = new IllegalArgumentException(
"Service Intent must be explicit: " + service);
throw ex;
} else {
Log.w(TAG, "Implicit intents with startService are not safe: " + service
+ " " + Debug.getCallers(2, 3));
}
}
}

既然,源码里是这样写的,那么这里有两种解决方法:

  • 设置Action和packageName:

谷歌推荐方法

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Intent mIntent = new Intent();
mIntent.setAction("XXX.XXX.XXX");//你定义的service的action
mIntent.setPackage(getPackageName());//这里你需要设置你应用的包名
context.startService(mIntent);
  • 将隐式启动转换为显示启动:
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public static Intent getExplicitIntent(Context context, Intent implicitIntent) {
// Retrieve all services that can match the given intent
PackageManager pm = context.getPackageManager();
List<ResolveInfo> resolveInfo = pm.queryIntentServices(implicitIntent, 0);
// Make sure only one match was found
if (resolveInfo == null || resolveInfo.size() != 1) {
return null;
}
// Get component info and create ComponentName
ResolveInfo serviceInfo = resolveInfo.get(0);
String packageName = serviceInfo.serviceInfo.packageName;
String className = serviceInfo.serviceInfo.name;
ComponentName component = new ComponentName(packageName, className);
// Create a new intent. Use the old one for extras and such reuse
Intent explicitIntent = new Intent(implicitIntent);
// Set the component to be explicit
explicitIntent.setComponent(component);
return explicitIntent;
}

调用方式如下:

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Intent mIntent = new Intent();
mIntent.setAction("XXX.XXX.XXX");
Intent eintent = new Intent(getExplicitIntent(mContext,mIntent));
context.startService(eintent);